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11210 libm should be cstyle(1ONBLD) clean
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--- old/usr/src/lib/libm/common/LD/sinhl.c
+++ new/usr/src/lib/libm/common/LD/sinhl.c
1 1 /*
2 2 * CDDL HEADER START
3 3 *
4 4 * The contents of this file are subject to the terms of the
5 5 * Common Development and Distribution License (the "License").
6 6 * You may not use this file except in compliance with the License.
7 7 *
8 8 * You can obtain a copy of the license at usr/src/OPENSOLARIS.LICENSE
9 9 * or http://www.opensolaris.org/os/licensing.
10 10 * See the License for the specific language governing permissions
11 11 * and limitations under the License.
12 12 *
13 13 * When distributing Covered Code, include this CDDL HEADER in each
14 14 * file and include the License file at usr/src/OPENSOLARIS.LICENSE.
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15 15 * If applicable, add the following below this CDDL HEADER, with the
16 16 * fields enclosed by brackets "[]" replaced with your own identifying
17 17 * information: Portions Copyright [yyyy] [name of copyright owner]
18 18 *
19 19 * CDDL HEADER END
20 20 */
21 21
22 22 /*
23 23 * Copyright 2011 Nexenta Systems, Inc. All rights reserved.
24 24 */
25 +
25 26 /*
26 27 * Copyright 2006 Sun Microsystems, Inc. All rights reserved.
27 28 * Use is subject to license terms.
28 29 */
29 30
30 31 #pragma weak __sinhl = sinhl
31 32
32 33 #include "libm.h"
33 34 #include "longdouble.h"
34 35
35 -/* SINH(X)
36 +/* BEGIN CSTYLED */
37 +/*
38 + * SINH(X)
36 39 * RETURN THE HYPERBOLIC SINE OF X
37 40 *
38 41 * Method :
39 42 * 1. reduce x to non-negative by SINH(-x) = - SINH(x).
40 43 * 2.
41 44 *
42 45 * EXPM1(x) + EXPM1(x)/(EXPM1(x)+1)
43 46 * 0 <= x <= lnovft : SINH(x) := --------------------------------
44 - * 2
47 + * 2
45 48 *
46 49 * lnovft <= x < INF : SINH(x) := EXP(x-MEP1*ln2)*2**ME
47 50 *
48 51 * here
49 52 * lnovft logarithm of the overflow threshold
50 53 * = MEP1*ln2 chopped to machine precision.
51 54 * ME maximum exponent
52 55 * MEP1 maximum exponent plus 1
53 56 *
54 57 * Special cases:
55 58 * SINH(x) is x if x is +INF, -INF, or NaN.
56 59 * only SINH(0)=0 is exact for finite argument.
57 60 *
58 61 */
62 +/* END CSTYLED */
59 63
60 64 static const long double C[] = {
61 65 0.5L,
62 66 1.0L,
63 67 1.135652340629414394879149e+04L,
64 68 7.004447686242549087858985e-16L
65 69 };
66 70
67 -#define half C[0]
68 -#define one C[1]
69 -#define lnovft C[2]
70 -#define lnovlo C[3]
71 +#define half C[0]
72 +#define one C[1]
73 +#define lnovft C[2]
74 +#define lnovlo C[3]
71 75
72 76 long double
73 77 sinhl(long double x)
74 78 {
75 - long double r, t;
79 + long double r, t;
76 80
77 81 if (!finitel(x))
78 - return (x + x); /* x is INF or NaN */
82 + return (x + x); /* x is INF or NaN */
83 +
79 84 r = fabsl(x);
85 +
80 86 if (r < lnovft) {
81 87 t = expm1l(r);
82 88 r = copysignl((t + t / (one + t)) * half, x);
83 89 } else {
84 90 r = copysignl(expl((r - lnovft) - lnovlo), x);
85 91 r = scalbnl(r, 16383);
86 92 }
93 +
87 94 return (r);
88 95 }
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