1 /* 2 * CDDL HEADER START 3 * 4 * The contents of this file are subject to the terms of the 5 * Common Development and Distribution License (the "License"). 6 * You may not use this file except in compliance with the License. 7 * 8 * You can obtain a copy of the license at usr/src/OPENSOLARIS.LICENSE 9 * or http://www.opensolaris.org/os/licensing. 10 * See the License for the specific language governing permissions 11 * and limitations under the License. 12 * 13 * When distributing Covered Code, include this CDDL HEADER in each 14 * file and include the License file at usr/src/OPENSOLARIS.LICENSE. 15 * If applicable, add the following below this CDDL HEADER, with the 16 * fields enclosed by brackets "[]" replaced with your own identifying 17 * information: Portions Copyright [yyyy] [name of copyright owner] 18 * 19 * CDDL HEADER END 20 */ 21 22 /* 23 * Copyright 2011 Nexenta Systems, Inc. All rights reserved. 24 */ 25 26 /* 27 * Copyright 2005 Sun Microsystems, Inc. All rights reserved. 28 * Use is subject to license terms. 29 */ 30 31 #pragma weak __nextafter = nextafter 32 #pragma weak _nextafter = nextafter 33 34 #include "libm.h" 35 #include <float.h> /* DBL_MIN */ 36 37 double 38 nextafter(double x, double y) 39 { 40 int hx, hy, k; 41 double ans; 42 unsigned lx; 43 volatile double dummy __unused; 44 45 hx = ((int *)&x)[HIWORD]; 46 lx = ((int *)&x)[LOWORD]; 47 hy = ((int *)&y)[HIWORD]; 48 k = (hx & ~0x80000000) | lx; 49 50 if (x == y) 51 return (y); /* C99 requirement */ 52 53 if (x != x || y != y) 54 return (x * y); 55 56 if (k == 0) { /* x = 0 */ 57 k = hy & 0x80000000; 58 ((int *)&ans)[HIWORD] = k; 59 ((int *)&ans)[LOWORD] = 1; 60 } else if (hx >= 0) { 61 if (x > y) { 62 ((int *)&ans)[LOWORD] = lx - 1; 63 k = (lx == 0) ? hx - 1 : hx; 64 ((int *)&ans)[HIWORD] = k; 65 } else { 66 ((int *)&ans)[LOWORD] = lx + 1; 67 k = (lx == 0xffffffff) ? hx + 1 : hx; 68 ((int *)&ans)[HIWORD] = k; 69 } 70 } else { 71 if (x < y) { 72 ((int *)&ans)[LOWORD] = lx - 1; 73 k = (lx == 0) ? hx - 1 : hx; 74 ((int *)&ans)[HIWORD] = k; 75 } else { 76 ((int *)&ans)[LOWORD] = lx + 1; 77 k = (lx == 0xffffffff) ? hx + 1 : hx; 78 ((int *)&ans)[HIWORD] = k; 79 } 80 } 81 82 k = (k >> 20) & 0x7ff; 83 84 if (k == 0x7ff) { 85 /* overflow */ 86 return (_SVID_libm_err(x, y, 46)); 87 #if !defined(__lint) 88 } else if (k == 0) { 89 /* underflow */ 90 dummy = DBL_MIN * copysign(DBL_MIN, x); 91 #endif 92 } 93 94 return (ans); 95 }