libdtrace: attempt to resolve FORWARD types to concrete types

*** 48,57 ****
--- 48,58 ----
  dt_xlator_create_member(const char *name, ctf_id_t type, ulong_t off, void *arg)
  {
          dt_xlator_t *dxp = arg;
          dtrace_hdl_t *dtp = dxp->dx_hdl;
          dt_node_t *enp, *mnp;
+         ctf_file_t *ctfp;
  
          if ((enp = dt_node_xalloc(dtp, DT_NODE_XLATOR)) == NULL)
                  return (dt_set_errno(dtp, EDT_NOMEM));
  
          enp->dn_link = dxp->dx_nodes;
*** 69,79 ****
           * the current member.  These refs will be used by dt_cg.c and dt_as.c.
           */
          enp->dn_op = DT_TOK_XLATE;
          enp->dn_xlator = dxp;
          enp->dn_xmember = mnp;
!         dt_node_type_assign(enp, dxp->dx_dst_ctfp, type, B_FALSE);
  
          /*
           * For the member itself, we use a DT_NODE_MEMBER as usual with the
           * appropriate name, output type, and member expression set to 'enp'.
           */
--- 70,87 ----
           * the current member.  These refs will be used by dt_cg.c and dt_as.c.
           */
          enp->dn_op = DT_TOK_XLATE;
          enp->dn_xlator = dxp;
          enp->dn_xmember = mnp;
!         /*
!          * XXX: Is it ok for the CTF of the type to not be from the dst ctf?
!          *
!          * I suspect it's actually unnecessary, but I'm also unclear on
!          * dynamic translators
!          */
!         dt_resolve_forward_decl(&ctfp, &type);
!         dt_node_type_assign(enp, ctfp, type, B_FALSE);
  
          /*
           * For the member itself, we use a DT_NODE_MEMBER as usual with the
           * appropriate name, output type, and member expression set to 'enp'.
           */